Golf competition ideas please

[Peck]

A simple solution is to allow the teams of 3 after finishing to select a 4th player at random from the teams of 4. The downside is that it means everyone in the 4 balls has to finish each hole if they can score and you have to trust them to do their best, rather than sat 3 putting on purpose because their teams scores are secured (if playing best 2 or 3 stableford scores from 4).

The upside is the added drama in the clubhouse of selecting the additional players to find out who's won.

Yes this is how our crowd would do it. Not quite sure about the OPs maths for his groupings though as per Mr Curta’s comment, we would just play 3x fourballs and a 3 ball going out first. We’d probably do best 3 stableford scores, bit more pressure for the 3 ball but lowers the likelihood of shenanigans from the 4s!

[deepreddave]

Not quite sure about the OPs maths for his groupings though as per Mr Curta’s comment...

The OP said they have 5 tee times booked hence the 5 groups, though using all 5 isn't compulsory but can allow the 3 balls to play quicker depending on how busy it is.

If there's more than one game then you could do a Ryder Cup style variation with 4BBB/singles within the 4s and set one 3 balls against the next day's 3 ball etc.

[Mr Curta]

The OP said they have 5 tee times booked hence the 5 groups, though using all 5 isn't compulsory but can allow the 3 balls to play quicker depending on how busy it is.

Ah okay, I still don't quite understand the grouping though. Wouldn't 5 groups of 3 make most sense and then do some fancy maths with the individual totals to create team results?

[deepreddave]

Ah okay, I still don't quite understand the grouping though. Wouldn't 5 groups of 3 make most sense and then do some fancy maths with the individual totals to create team results?

It's an option but the standard formats involve even numbers.

[Mr Curta]

It's an option but the standard formats involve even numbers.

The OP had 3 groups of 3, which gave a total of 17...